Homework Help thread

[Rolcol]

Welcome to the Homework Help thread, inspired by PkRsViRUS's idea. If you have any questions on any of your school work post them here.

But please understand that you can't ask people do you work for you, but rather help you with it :D.

Approved Tutors:

• Rolcol- Intermediate Algebra (Algebra 2) and below. Some Science, too.
• Chaoszero- Math Grade 10 and below. Canadian Social Studies. Some Science, too.
• Isa- Spanish (native speaker)
• pdlqboy- Language Arts 9th Grade and below
• Tetsuka- Math below Calculus. Computer Science in C#. English (all). Science Biology, Chem, Physics, and all applied sciences. Spanish.
  Social Studies, Gov/Eco, US History, Texas History, World History, World Geography.

[To become an approved tutor you must help around and display that you are qualified to help]

[RoyalSOULJA219]

Originally Posted by PkRsViRUS

Ok... i know this's gaming forum... but i need help with math. i've spent 37 on one freakn problem.... tooooo long... PLEASE help!


5y + 5 - (-3y) - 15

8y -10

the minus sign in front of the negative switches it to positive then you just combine like terms...

[Flightbolt]

Haha basic algebra anyone wanna help me with physics, biology or the equations of a line (Slope/y-intercept)?

I understand it, but I'm to lazy to do it myself =P.

[Flightbolt]

Anyone want to help me solve this?

"A line passes through the points (2,1) and has the same y-intercept as the line having the equation 6x- 5y - 90 = 0

Find the line and state it in the form: Ax + By +C = 0"

I need the slope of the line and I'll be all good.

So far I have:

1 = m(2) + b

If I use the formula for slope of a line ( m = (y2- y1)/(x2-x1) ) would that work? Or am I just insane?

EDIT: No that won't work because I can't determine whether the line is perpendicular or parallel.

[Tetsuka]

Tetsuka helped chaos, anyone need math help I'm usually on MSN HoeskyxJoesky@hotmail.com :P

[Flightbolt]

Originally Posted by Tetsuka

Tetsuka helped chaos, anyone need math help I'm usually on MSN HoeskyxJoesky@hotmail.com :P

Tets and Roly FTW <3 <3.

Answer is:

19x -2y -36 = 0

:D!

[Zel-EX]

This is a good Idea for a thread! But I need help, too... I suck at math. Heres a scanned picture of my assignment.
http://i181.photobucket.com/albums/x.../homework1.png
I just need to know how to do it. Thanks!:)

[Rolcol]

Originally Posted by DarkDave64

This is a good Idea for a thread! But I need help, too... I suck at math. Heres a scanned picture of my assignment.
http://i181.photobucket.com/albums/x.../homework1.png
I just need to know how to do it. Thanks!:)

The basic thing here is to simplify. Look at both of them and determine if you can divide anything out of both the top and the bottom without changing the content. For #2 as an example, they are proportionate.

(7/3) = (14/6). Dividing both the numerator and the denominator by 2 gives you (7/3) which is the same as the first one.

Fraction 1 in #3 can be reduced by dividing both the numerator and the denominator by 2 and fraction 2 in #3 can be reduced by dividing both the numerator and the denominator by 3. Once they are simplified you can compare.

---
Part 2


(to make it simpler on yourself be sure to reduce your fractions before doing what's below)

When you're solving you have to cross multiply. Meaning you multiply the denominator of the first fraction by the numerator of the second fraction and set it equal to the numerator of the first fraction multiplied by the denominator of the second fraction.

You then divide to get the variable on its own on one side of the equal sign to get your answer.

link: http://i56.photobucket.com/albums/g176/Rolcol/problem13.gif

[Flightbolt]

Originally Posted by DarkDave64

This is a good Idea for a thread! But I need help, too... I suck at math. Heres a scanned picture of my assignment.
http://i181.photobucket.com/albums/x.../homework1.png
I just need to know how to do it. Thanks!:)

Aight here's the way that I solve fraction-ratio problems is like so:

When you are given two fractions such as question 1, the first thing you need to do is make sure both fractions have a common denominator. You can go about this in two ways:

The harder way: Find multiples of both numbers, for fraction 1's denominator it would be:
8, 16,24,43,40 ect.
Fraction 2's denominator's multiples would be:
3,6,9,12,15,18,21,24 ect.

Once you find two numbers that match (In the case 24) set that as your LCD (Lowest common denominator).

The easier way: Is just to just multiple the two denominators together. So 8 x 3 = 24. As you can see you get the same number, 24. This may not always be true, for example ( 6 and 4, the LCD is 12, even though when multiplied you get 24).

The golden rule of fractions is this: Whatever you do to the bottom, YOU MUST DO TO THE TOP.

So to solve:

5/8 and 2/3

The LCD is 24

5/8 = 8 x 3 = 24
*Whatever you do to the bottom you do to the top*
5 x 3 =15

So you now have: 15/24

Fraction 2:

The LCD is 24

2/3 = 3 x 8 =24
*Whatever you do to the bottom you do to the top*
2 x 8 = 16

You now have: 16/24, so no, these are not proportioned.

I gotta go, Rolcol will fill you in on how to find variables.

[Zel-EX]

Rolcol and Chaoszero, thank you both! You just helped me bring up that 47 average I have in math right now!(lol yes, I really do have a 47 in math) karma to you both! And Rolcol, the example isn't nessessary... but thanks anyway;)